Armstrong numbers in c++

If sum of cubes of each digit of the number is equal to the number itself, then the number is called an Armstrong number.

For example, 153 = ( 1 * 1 * 1 ) + ( 5 * 5 * 5 ) + ( 3 * 3 * 3 )
        
Write a program that prints all Armstrong numbers from 1-1000.

Solution:

	#include<iostream>
	#include<conio.h>
	using namespace std;
	int main()
	{
	int rem,res,div;
	for(int i = 1; i<=1000; i++)
	{
	rem = i%10;
	div = i/10;
	res = rem*rem*rem;
	if(div>=1)
	{
	rem = div%10;
	div = div/10;
	res = res + rem*rem*rem;
	if(div>=1)
	{
	rem = div%10;
	div = div/10;
	res = res + rem*rem*rem;
	}
	}
	if(res == i)
	cout<<res<<endl;
	}
	getch();
	return 0;
	}

view raw main.c hosted with ❤ by GitHub

OUTPUT: